Let us consider rectangles whose height, \textbf{h}, and width, \textbf{w}, are both integers. We call such rectangles integral rectangles. In this problem, we consider only wide integral rectangles, i.e., those with \textbf{w} > \textbf{h}. We define the following ordering of wide integral rectangles. Given two wide integral rectangles, \begin{enumerate} \item The one shorter in its diagonal line is smaller, and \item If the two have diagonal lines with the same length, the one shorter in its height is smaller. \end{enumerate} \includegraphics{https://static.e-olymp.com/content/38/3832f6fc845cbaf4633f3d9cac53e1770bb7ed26.jpg} Given a wide integral rectangle, find the smallest wide integral rectangle bigger than the given one. \InputFile The entire input consists of multiple datasets. The number of datasets is no more than \textbf{100}. Each dataset describes a wide integral rectangle by specifying its height and width, namely \textbf{h} and \textbf{w}, separated by a space in a line, as follows. \textbf{h w} For each dataset, \textbf{h} and \textbf{w} (> \textbf{h}) are both integers greater than \textbf{0} and no more than \textbf{100}. The end of the input is indicated by a line of two zeros separated by a space. \OutputFile For each dataset, print in a line two numbers describing the height and width, namely \textbf{h} and \textbf{w} (> \textbf{h}), of the smallest wide integral rectangle bigger than the one described in the dataset. Put a space between the numbers. No other characters are allowed in the output. For any wide integral rectangle given in the input, the width and height of the smallest wide integral rectangle bigger than the given one are both known to be not greater than \textbf{150}. In addition, although the ordering of wide integral rectangles uses the comparison of lengths of diagonal lines, this comparison can be replaced with that of squares (self-products) of lengths of diagonal lines, which can avoid unnecessary troubles possibly caused by the use of floating-point numbers.